1 条题解
-
0
Pascal :
var str:ansistring; n,i,j,sum,ans:longint; begin readln(n); readln(str); str:=str+str+str; ans:=0; for i:=n+1 to n+n do begin sum:=0; for j:=i downto 1 do if (str[i]=str[j]) or (str[j]='w') then else break; sum:=i-j; for j:=i+1 to n+n+n do if (str[i]=str[j]) or (str[j]='w') then else break; sum:=sum+j-i; if sum>ans then ans:=sum; end; writeln(ans); end.
- 1
信息
- ID
- 3454
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者