1 条题解

  • 0
    @ 2025-4-14 18:43:49

    C :

    #include <stdio.h>
    int main (void)
    {
        int T,i;
        double a[5]={0};
        double b;
        double avg;
        scanf("%d",&T);
        while(T--){
            scanf("%lf",&b);
            for(i=0;i<5;i++){
                scanf("%lf",&a[i]);
            }
            avg=(a[0]+a[1]+a[2]+a[3]+a[4])/5.0;
            if(b>=avg){
                printf("Xiaoming is full of confidence\n");
            }
            else{
                printf("Xiaoming is panic to death\n");
            }
        }
        return 0;
    }
    
    

    C++ :

    #include <iostream>
    #include <fstream>
    using namespace std;
    int main()
    {
      //  ifstream cin;
     //   ofstream cout;
      //  cin.open("f.in");
      //  cout.open("f.out");
    
        int testcase;
        cin>>testcase;
        while(testcase--)
        {
            double tmp,avg=0;
            double tar,res=0;
            cin>>tar;
            for(int i=0;i<5;i++)
            {
                cin>>tmp;
                res+=tmp;
            }
            avg=res/5.0;
            if(avg<=tar)
            {
                cout<<"Xiaoming is full of confidence"<<endl;
            }
            else
            {
                cout<<"Xiaoming is panic to death"<<endl;
            }
    
        }
        return 0;
    }
    
    
    • 1

    信息

    ID
    3373
    时间
    1000ms
    内存
    64MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者