1 条题解
-
0
C :
#include <stdio.h> #include <math.h> #include <stdlib.h> #include <time.h> int main() { // freopen("in","r",stdin); // freopen("out","w",stdout); int n=1; //while(scanf("%d",&n )!=EOF){ double term = 1.0, sign = 1,sum = 0; while (fabs(term) >= 1e-4) { term = sign / n; sum = sum + term; sign = -sign; n++; } printf("%lf\n", sum); //} return 0; }
C++ :
#include<stdio.h> #include<math.h> int main() { double sum = 0.0 ,i; for(i = 1.0;fabs(1/i) > 1e-4;i++) { sum = sum + 1/(i*pow(-1,i + 1)); } printf("%0.6lf\n",sum); return 0; }
- 1
信息
- ID
- 3361
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者