C++ :

#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <iostream>
#include <algorithm>
#include <stack>
#include <queue>
#include <cmath>
#include <string>
#include <set>
#include <map>
#define maxn 0
 
using namespace std ;
 
int day_diff(int year_start, int month_start, int day_start
   , int year_end, int month_end, int day_end)
{
 int y2, m2, d2;
 int y1, m1, d1;
  
 m1 = (month_start + 9) % 12;
 y1 = year_start - m1/10;
 d1 = 365*y1 + y1/4 - y1/100 + y1/400 + (m1*306 + 5)/10 + (day_start - 1);
 
 m2 = (month_end + 9) % 12;
 y2 = year_end - m2/10;
 d2 = 365*y2 + y2/4 - y2/100 + y2/400 + (m2*306 + 5)/10 + (day_end - 1);
  
 return (d2 - d1);
}
 
int main ()
{
    int n, y, m, d ;
    long long sum ;
    scanf ("%d", &n) ;
    while (n--)
    {
        scanf ("%d%d%d", &y, &m, &d) ;
        if (y < 1931)
        {
            printf ("鬼子还没来\n") ;
            continue ;
        }
        else if (y == 1931 && m < 9)
        {
            printf ("鬼子还没来\n") ;
            continue ;
        }
        else if (y == 1931 && m == 9 && d < 18)
        {
            printf ("鬼子还没来\n") ;
            continue ;
        }
         
        if ((y > 1931 && y < 1937) || (y==1931 && m > 9) || (y==1931 && m==9 && d>=18) || (y==1937 && m < 7) || (y==1937 && m==7 && d<=6))
        {
            sum = day_diff (1931, 9, 18, y, m, d) ;
            printf ("抗战开始%lld天\n", sum) ;
            continue ;
        }
         
        if ((y > 1937 && y < 1945) || (y==1937 && m > 7) || (y==1937 && m==7 && d>=7) || (y==1945 && m < 8) || (y==1945 && m==8 && d<=14))
        {
            sum = day_diff (y, m, d, 1945, 8, 14) + 1 ;
            printf ("离抗战胜利还有%lld天\n",sum) ;
            continue ;
        }
         
        if ((y==1945 && m > 8 && m < 9) || (y==1945 && m==8 && d>=15)  || (y==1945 && m==9 && d<=2))
        {
            printf ("全国欢庆胜利\n") ;
            continue ;
        }
         
        if (m > 9 || (m==9 && d>=3))
        {
            sum = day_diff (y, m, d, y+1, 9, 3) ;
            printf ("距离下一个纪念日还有%lld天\n", sum) ;
            continue ;
        }
         
        if (m < 9 || (m==9 && d<3))
        {
            sum = day_diff (y, m, d, y, 9, 3) ;
            printf ("距离下一个纪念日还有%lld天\n", sum) ;
            continue ;
        }
    }
 
    return 0 ;
}