1 条题解
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0
C :
#include<stdio.h> #include<math.h> int main() { double a, b, c, C; scanf("%lf%lf%lf", &a, &b, &c); C = pow(b, 2) - 4 * a * c; if(C == 0) printf("x1=%.3lf x2=%.3lf\n", -b / (2 * a), -b / (2 * a)); if(C < 0) printf("x1=%.3lf+%.3lfi x2=%.3lf-%.3lfi\n",-b / (2 * a), sqrt(-C) / (2 * a), -b / (2 * a), sqrt(-C) / (2 * a)); if(C > 0) printf("x1=%.3lf+%.3lf x2=%.3lf-%.3lf\n",-b / (2 * a), sqrt(C) / (2 * a), -b / (2 * a), sqrt(C) / (2 * a)); }
C++ :
#include <stdio.h> #include <cmath> #include <string.h> #include <cstdlib> #include <iostream> #define eps 1e-6 using namespace std; int main() { double a, b, c, disc, x1, x2, real, imag; scanf("%lf%lf%lf", &a, &b, &c); disc = b * b - 4 * a * c; if(fabs(disc) <= eps) { printf("x1=%.3lf ", -b / (2 * a)); printf("x2=%.3lf\n", -b / (2 * a)); } else if(fabs(disc > eps)) { x1 = (-b + sqrt(disc)) / (2 * a); x2 = (-b - sqrt(disc)) / (2 * a); printf("x1=%.3lf x2=%.3f\n", x1, x2); } else { real = -b / (2 * a); imag = sqrt(-disc) / (2 * a); printf("x1=%.3f+%.3fi ", real, imag); printf("x2=%.3f-%.3fi\n", real, imag); } return 0; }
- 1
信息
- ID
- 2714
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者