1 条题解

  • 0
    @ 2025-4-12 21:54:23

    C :

    #include<stdio.h>
    int main()
    {
    	int n,a[1010];
    	int i,j,t;
    	int count;
    	while(scanf("%d",&n),n)
    	{
    		count=0;
    		for(i=0;i<n;i++)
    			scanf("%d",&a[i]);
    		for(i=1;i<n;i++)
    			for(j=1;j<=n-1;j++)
    				if(a[j-1]>a[j])
    				{
    					t=a[j-1];
    					a[j-1]=a[j];
    					a[j]=t;
    					count++;
    				}
    		printf("%d\n",count);
    	}
    }
    

    C++ :

    #include <stdio.h>
    #include <stdlib.h>
    
    int a[1005], t[1005];
    long long sum;
    
    void Merge(int l, int m, int r) {
    	int p = 0;
    	int i = l, j = m + 1;
    	while (i <= m && j <= r) {
    		if (a[i] > a[j]) {
    			t[p++] = a[j++];
    			sum += m - i + 1;
    		} else
    			t[p++] = a[i++];
    	}
    	while (i <= m)
    		t[p++] = a[i++];
    	while (j <= r)
    		t[p++] = a[j++];
    	for (i = 0; i < p; i++)
    		a[l + i] = t[i];
    }
    
    void MergeSort(int l, int r) {
    	int m;
    	if (l < r) {
    		m = (l + r) / 2;
    		MergeSort(l, m);
    		MergeSort(m + 1, r);
    		Merge(l, m, r);
    	}
    }
    
    int main() {
    	int n, i;
    	while (scanf("%d", &n) != EOF, n) {
    		sum = 0;
    		for (i = 0; i < n; i++)
    			scanf("%d", &a[i]);
    		MergeSort(0, n - 1);
    		printf("%lld\n", sum);
    	}
    	return 0;
    }
    

    Pascal :

    var a:array[1..1000]of longint;n,s,i,j:longint;
    begin
     readln(n);
     while n<>0 do
      begin
       s:=0;
       for i:=1 to n do
        read(a[i]);
       for i:=1 to n do
        for j:=1 to n-i do
         if a[j]>a[j+1] then begin a[j]:=a[j]+a[j+1];a[j+1]:=a[j]-a[j+1];a[j]:=a[j]-a[j+1];s:=s+1 end;
       writeln(s);
       readln(n)
      end
    end.
    
    • 1

    信息

    ID
    2323
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者