1 条题解

  • 0
    @ 2025-4-12 21:54:22

    C :

    #include<stdio.h>
    int main()
    {
      int n;
      while(scanf("%d",&n)&&n!=0)
        printf("%d\n",n/2);
    return 0;
    }
    

    C++ :

    #include<iostream>
    using namespace std;
    
    int caculate(int n)
    {
    	if(n<=2)
    		return 0;
    	else if(n==3&&n==4)
    	{
    		return 1;
    	}
    	else
    	{
    		if(n%2)
    		{
    			return (n-1)/2;
    		}
    		else
    		{
    			return n/2;
    		}
    	}
    }
    
    int main()
    {
    	int N;
    	while(cin>>N)
    	{
    		int count=0;
    		if(N<=0)
    		{
    			return 0;
    		}
    		else
    		{
    			count=caculate(N);
    		}
    		cout<<count<<endl;
    	}
    	return 0;
    }
    

    Java :

    import java.util.*;
    public class Main {
    	public static void main(String[] args) {
    		Scanner input=new Scanner(System.in);
    		int sum=0;
    		while(true){
    			int n=input.nextInt();
    			if(n==0){
    				break;
    			}
    			int left=n;
    			while(left>=3){
    				int yu=left%3;
    				int kong=left/3;
    				sum+=kong;
    				left=yu+kong;
    			}
    			if(left==2){
    				sum+=1;
    			}
    			System.out.println(sum);
    			sum=0;
    		}
    
    	}
    
    }
    
    

    Python :

    # coding=utf-8
    sum1 = 0
    while 1:
        a = int(input())
        if a==0:
            break
        while 1:
            b = a//3 #取整
            sum1 = sum1+b
            c = a%3  #取余
            if b+c>=3:
                a = b+c
            elif b+c==2:
                sum1 = sum1 + 1
                break
            else:
                break
        print(sum1)
        sum1 = 0
            
    
    
    • 1

    信息

    ID
    2196
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者