1 条题解
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0
C :
int main(int argc, char* argv[]) { int n,a[101][101],i,j; while(~scanf("%d",&n)) { for(i=0;i<n;i++) for(j=0;j<n;j++) scanf("%d",&a[i][j]); for(i=0;i<n;i++) {for(j=0;j<n-1;j++) printf("%d ",a[j][i]); printf("%d\n",a[j][i]); } } return 0; }
C++ :
#include <stdio.h> int main() { int n,a[101][101],i,j; scanf("%d",&n); while(n!=0) { for(i=0;i<n;i++) for(j=0;j<n;j++) scanf("%d",&a[i][j]); for(i=0;i<n;i++) { for(j=0;j<n-1;j++) printf("%d ",a[j][i]); printf("%d\n",a[n-1][i]); } n=0; scanf("%d",&n); } return 0; }
Pascal :
var n,i,j,b:integer; a:array[1..100,1..100]of integer; begin while not eof do begin readln(n); if n=1 then begin readln(b);writeln(b); end else begin for i:=1 to n do for j:=1 to n do read(a[i,j]); for i:=1 to n do begin for j:=1 to n-1 do write(a[j,i],' '); writeln(a[j+1,i]); end; end; end; end.
Java :
import java.util.Scanner; public class Main{ public static void main(String[] args){ Scanner in = new Scanner(System.in); while(in.hasNextInt()){ int x = in.nextInt(); int[][] a = new int[x][x]; for(int i=0;i<x;i++){ for(int j=0;j<x;j++){ a[i][j] = in.nextInt(); } } for(int i=0;i<x;i++){ for(int j=0;j<x;j++){ if(j==x-1) System.out.print(a[j][i]); else System.out.print(a[j][i]+" "); } System.out.println(); } } } }
- 1
信息
- ID
- 1888
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者