1 条题解

  • 0
    @ 2025-4-12 21:45:15

    C :

    #include <stdio.h>
    int main() {
            int h = 10;
            float x1=2,y1=2,x2=-2,y2=2,x3=-2,y3=-2,x4=2,y4=-2;
            float x,y,d1,d2,d3,d4;
            scanf("%f %f", &x, &y);                                     
            d1=(x-x1) * (x-x1)+(y-y1) * (y-y1);
            d2=(x-x2) * (x-x2)+(y-y2) * (y-y2);
            d3=(x-x3) * (x-x3)+(y-y3) * (y-y3);
            d4=(x-x4) * (x-x4)+(y-y4) * (y-y4);
            if (d1>1 && d2>1 && d3>1 && d4>1) h=0;       
            printf("%.2f\n", h + .0);
            return 0;
    }
    

    C++ :

    #include <stdio.h>
    int main() {
    	int h = 10;
    	float x1=2,y1=2,x2=-2,y2=2,x3=-2,y3=-2,x4=2,y4=-2;
    	float x,y,d1,d2,d3,d4;
    	scanf("%f %f", &x, &y);					/*求该点到各中心点的距离*/
    	d1=(x-x1) * (x-x1)+(y-y1) * (y-y1);
    	d2=(x-x2) * (x-x2)+(y-y2) * (y-y2);
    	d3=(x-x3) * (x-x3)+(y-y3) * (y-y3);
    	d4=(x-x4) * (x-x4)+(y-y4) * (y-y4);
    	if (d1>1 && d2>1 && d3>1 && d4>1) h=0;	/*判断该点是否在塔外*/
    	printf("%.2f\n", h + .0);
    	return 0;
    }
    
    

    Pascal :

    
    
    
    
    var 
      x,y:double;
      
    begin
      readln(x,y);
      x:=abs(abs(x)-2);
      y:=abs(abs(y)-2); //均移动到第一象限
      if( x*x+y*y<=1 ) then writeln(10.00:0:2)
        else writeln(0.00:0:2);
    end.
    
    
    
    

    Java :

    import java.util.*;
    public class Main {
    	public static void main(String args[]) {
    		Scanner cin = new Scanner(System.in);
    		double x,y,d,h;
    		x=Math.abs(cin.nextDouble());
    		y=Math.abs(cin.nextDouble());
    		d=Math.sqrt((x-2)*(x-2)+(y-2)*(y-2));
    		if(d<1)
    			h=10.00;
    		else
    			h=0.00;
    		System.out.printf("%.2f\n",h);
    	}
    }
    

    Python :

    x,y = [float(x) for x in raw_input().split()]
    if (abs(x)-2)**2 + (abs(y)-2)**2 < 1:
      print "10.00"
    else:
      print "0.00"
    
    • 1

    信息

    ID
    1531
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者