1 条题解
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0
C :
#include<stdio.h> #include<string.h> int main() { int n,s,f,m; scanf("%d",&n); s=n/3600; f=(n%3600)/60; m=((n%3600)%60); printf("%d:%d:%d",s,f,m); return 0; }
C++ :
#include<iostream> using namespace std; int main(void) { unsigned long long n,a,m,s,w; cin>>n; a=n/3600; w=n%3600; m=w/60; w=w%60; s=w; cout<<a<<":"<<m<<":"<<s<<'\n'; return 0; }
Pascal :
var n,s,f,m,s1,f1,m1:longint; begin readln(n); s:=n div 3600; s1:=n mod 3600; f:=s1 div 60; f1:=s1 mod 60; write(s,':',f,':',f1); end.
Java :
import java.util.*; public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); while (in.hasNext()){ int m = in.nextInt(); print(m); } } //写一个方法把秒转为时:分:秒输出 private static void print(int time){ int shi = time/3600 ; int fen = (time - shi * 3600 ) / 60 ; int miao = (time - shi * 3600 - fen * 60 ) ; System.out.println(shi+":"+fen+":"+miao); } }
- 1
信息
- ID
- 1303
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者