1 条题解

  • 0
    @ 2025-4-12 21:43:13

    C :

    #include <stdio.h>
    int main(void)
    {
    	int a,n=8,i=0,x[100];
    	scanf("%d",&a);
    	for (i=0;;i++)
    	{
    		if (a>=n)
    		{
    			x[i]=a%n;
    			a=a/n;
    		}
    		else 
    		break;
    	}
    	printf("%d",a);
    	i--;
    	for(;i>=0;i--)
    	{
    		printf ("%d",x[i]);
    	}
    	return 0;
    }
    

    C++ :

    #include <stdio.h>
    int a[100000];
    int main()
    {
    	int n;
    	while(scanf("%d",&n)!=EOF)
    	{
    		int i=0;
    		while(n)
    		{
    			a[i++]=n%8;
    			n/=8;
    		}
    		for(int j=i-1;j>=0;j--)
    		printf("%d",a[j]);
    		printf("\n");
    	}
    	return 0;
    }
    

    Pascal :

    var x,i,j:longint;
        a:array[1..99999]of longint;
    begin
      readln(x);
      repeat
      inc(j);
      a[j]:=x mod 8;
      x:=x div 8;
      until x=0;
      for i:=j downto 1 do
      write(a[i]);
    end.
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    
    	public static void main(String[] args) {
    		
    
    		Scanner cin = new Scanner(System.in);
    		int a;
    		String result;
    		while (cin.hasNext()) {
    			a = cin.nextInt();
    			
    			System.out.println(Integer.toOctalString(a));
    		}
    	}
    }
    
    
    • 1

    信息

    ID
    1261
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    (无)
    递交数
    0
    已通过
    0
    上传者