1 条题解
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0
C++ :
#include <cmath> #include <cstdio> #include <cstring> using namespace std; double dis(double a, double b, double c, double d) { return sqrt((a - c) * (a - c) + (b - d) * (b - d)); } int main() { //freopen("Problem2.in", "r", stdin); //freopen("Problem2.out", "w", stdout); double x1, x2, x3, y1, y2, y3; double d1, d2, d3, r1, r2, r3; while (scanf("%lf %lf %lf %lf %lf %lf", &x1, &y1, &x2, &y2, &x3, &y3) != EOF) { d1 = dis(x1, y1, x2, y2); d2 = dis(x2, y2, x3, y3); d3 = dis(x1, y1, x3, y3); r1 = (d3 + d1 - d2) / 2; r2 = (d1 + d2 - d3) / 2; r3 = (d2 + d3 - d1) / 2; printf("%.0lf\n", r1); printf("%.0lf\n", r2); printf("%.0lf\n", r3); } return 0; }
Java :
import java.io.*; import java.util.*; public class Main{ final static Scanner jin=new Scanner(System.in); public static void main(String args[]){ while(jin.hasNextInt()){ int ax=jin.nextInt(); int ay=jin.nextInt(); int bx=jin.nextInt(); int by=jin.nextInt(); int cx=jin.nextInt(); int cy=jin.nextInt(); double ab=Math.sqrt((ax-bx)*(ax-bx)+(ay-by)*(ay-by)); double bc=Math.sqrt((cx-bx)*(cx-bx)+(cy-by)*(cy-by)); double ca=Math.sqrt((ax-cx)*(ax-cx)+(ay-cy)*(ay-cy)); System.out.println((int)((ab+ca-bc)/2)); System.out.println((int)((ab+bc-ca)/2)); System.out.println((int)((bc+ca-ab)/2)); } } }
- 1
信息
- ID
- 1031
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者